AE=2cm,BE=3cm,AC=15cm and find AF
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Answer:
In △ABC, DE is parallel to BC
Thus, DE divides the two sides AB and AC proportionally.
Thus,
AB
AD
=
AC
AE
Thus, △ABC∼△ADE
AD
AB
=
AE
AC
=
DE
BC
[C.S.C.T.]
Now,
AE
AC
=
DE
BC
⇒DE=
AC
AE×BC
⇒DE=
5
2×10
[ ∵AC=(AE+EC)=2+3=5]
⇒DE=4 cm
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