AEB and DEC are semicircles if ABCD is a square of side 16cm. find the area of shaded region.
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Answered by
3
Answer:
Each side of square = 16cm
Are of square =16 × 16 cm²= 256cm²
Radius of semicircle = 16/2 cm =8cm
Area of both semicircles =Area of circle
=> 22/7× 8×8= 201.14cm²
Area of shaded region = Area of square-Area of semicircles
=> Area of shaded region =( 256-201.14 )cm²=>54.86cm²
Answered by
6
Answer:
Step-by-step explanation:
- Given=>Side of square=>16cm.
So area of square=>16*16
=>256cm^2.
- Diameter of semi-circle=>16cm.
- Radius of semi-circle=>16/2
=>8cm.
- So are of semi-circle=>1/2(πr^2).
- As semi-circle are two=2*1/2(πr^2)
=>πr^2
=>3.14(8)^2
=>3.14(64)
=>200.96cm^2.
—So area of shaded portion =>Area of Square- Area of circle.
=>256-200.96
=>55.04cm^2.
So the area of the shaded portion is 55.04cm^2 which is the required answer.
HOPE IT HELPS.
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