Question

aera of quadrilateral whose diagonal is 20 cm long and perpendicular to this diagonal from other vertices are of length 9 cm and 15 cm.​

Answer 1

Step-by-step explanation:

Given ABCD is a quadrilateral with AC=20cm and BP=9cm & OD=15cm and BP⊥AC & OD⊥AC

area of ΔABC=

2

1

×AC×BP=

2

1

×20×9=90cm

2

[Area of ΔABC−90cm

2

]

Area of ΔADC=

2

1

×AC×OD=

2

1

×20×15=150cm

2

Area of [ΔADC=150cm

2

]

Area of quadrilateral =area of ΔADC+ area of Δ ABC

=90+150

Area of quadrilateral (ABCD)=240cm

2

Hence area of quadrilateral ABCD is 240cm

2

.

solution