aera of rectangle 48 cm2 it's breadth is6 cm find its perimeter
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Answer:
28cm
Step-by-step explanation:
Area of rectangle = breadth×length= 6×y= 48cm²
Length of this rectangle is unknown = y
Area÷breadth = length = 48÷6 = 8cm
Perimeter of rectangle = 2× (l+b) = 2× (8+6) = 2×14
= 28 cm
So, perimeter of this rectangle is 28cm
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☆ Solution ☆
Given :-
- Area of the rectangle is 48 cm².
- The breadth of the breadth is 6 cm
To Find :-
- The perimeter of the rectangle
Step-by-Step-Explaination :-
Let,
- The length of the rectangle be l
As we know that :-
Area of the rectangle = length × breadth
Where,
- Area of the rectangle = 48 cm²
- Length of the rectangle = l
- Breadth of the rectangle = 6 cm
Putting the respective value,
48 = l × 6
l = 48/6
l = 8
Thus,
The length of the rectangle is 8 cm .
Now,
As we know that :-
Perimeter of rectangle = 2 ( length + breadth )
Where,
- Length of the rectangle = 8 cm
- Breadth of the rectangle = 6 cm
Putting the respective value,
Perimeter of the rectangle = 2 ( 8 + 6 )
Perimeter of the rectangle = 2 × 14
Perimeter of the rectangle = 28
Hence,
The perimeter of the rectangle is 28 cm
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