Aeroplane covers four distance at different speeds of 100,200,300,00 kms/hr.the average speed is?
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We can solve this better by using the direct formula for fetching average speeds.
= 2 (S1 S2) / (S1+S2)
Case 1 taking S1 = 100, S2 = 200
= 2*100*200/(100+200)
= 40000/300
= 400/3
= 2 (S1 S2) / (S1+S2)
Case 2 taking S1 = 300, S2 = 400
= 2*300*400 ( (300+400)
= 240000/700
= 2400/7
Case 3
S1 = 400/3, S2 = 2400/7
= 2 (S1 S2) / (S1+S2)
= (2 * 400/3 * 2400/7) / (400/3+2400/7)
= (1920000/21) / (10000/21)
= 1920000/21 * 21/10000
= 1920000/10000
= 192 km/hr is the required average speed.
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