Question

aeroplane left 30 minutes late than its secured time and in order to reach densitnation 3000 km away in time it has increase to speed of Aeroplane by 250 km/h from its usual speed. determinedmne its usual speed

Answer 1

Let the speed of Aeroplane be x km/h.

Distance/Speed = time

Forming the equation with the given conditions,

$\frac{3000}{ x } - \frac{3000}{x + 250} = \frac{1}{2} \\ {x}^{2} + 250x - 1500000 = 0 \\ x = 125( \sqrt{97} - 1) \\ x = 1106$
Therefore Original speed of aeroplane = 1106km/h (approx.)