Physics, asked by mssampath13850, 9 months ago

aeroplane rises vertically with a speed of 100 metre per second the aeroplane has wings span 10m and horizontal component of Earth's magnetic field perpendicular to wings is 5×10^-3Wb/m^2 the the induced emf across the ends of wings​

Answers

Answered by chaithanya305
4

Answer:

once see the diagram

Explanation:

Given

v=100m/s^2

l=10m

teta =45

tan teta=Bo/B

B=Bo

B=5×10^-3

we e=vBl

=100×5×10^-3×10

e=5v

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