aeroplane rises vertically with a speed of 100 metre per second the aeroplane has wings span 10m and horizontal component of Earth's magnetic field perpendicular to wings is 5×10^-3Wb/m^2 the the induced emf across the ends of wings
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Answer:
once see the diagram
Explanation:
Given
v=100m/s^2
l=10m
teta =45
tan teta=Bo/B
B=Bo
B=5×10^-3
we e=vBl
=100×5×10^-3×10
e=5v
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