af a+b+c=6 And ab + bc +ca=15, than a² + b²+c²=
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2
Answer:
6
Step-by-step explanation:
According to question
a+b+c=6
squaring on both sides
(a+b+c)^2=(6)^2
a^2+b^2+c^2+2ab+2bc+2ca=36
a^2+b^2+c^+2(ab+bc+ca)=36
a^2+b^2+c^2+2(15)=36{given above}
a^2+b^2+c^2=36-30=6
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