Question

.) Afootpath of uniforem width 5m ruens all round the inside of orectangular field 36 m long and 32m wide.find the area of the path.​

Answer 1

Answer:

x=3m

Step-by-step explanation:

Let the width of footpath=x

total area of rectangle ABCD = area of footpath + area of EFGH

⇒50×38=492+[(50−2x)×(38−2x)]

⇒1900=492+[1900−100x−176x+4x^2 ]

⇒4x^2 −176x+492=0

⇒x^2 −44x+123=0

⇒(x−3)(x−41)=0

∴x=3m

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Answer 2

Answer:

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