Aftab Hells his daughter" seven year
ago. I was seven times as old as
you were then, also, three year from
now I shall be three times as old
as you will be. Represent this
situation algebraically mel graphicall
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Solution :
Let the present age of aftab be x.
And, his daughter be y.
Seven years ago,
Aftab's age = x - 7
Daughter's age = y - 7
According to the question;
(x - 7) = 7 (y - 7)
⇒ x - 7 = 7y - 49
⇒ x - 7 + 49 - 7y = 0
⇒ x + 42 - 7y = 0
⇒ x - 7y + 42 = 0
Three years hence,
Aftab's age = x + 3
Daughter's age = y + 3
According to the question ;
( x + 3) = 3 (y + 3)
⇒ x + 3 = 3y + 9
⇒ x + 3 - 9 = 3y
⇒ x - 6 - 3y = 0
[For graph, Refer to the attached picture]
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nikhilroy27:
thankyou very much
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