Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” (Isn’t this interesting?) Represent this situation algebraically and graphically.
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Answer:
Step-by-step explanation:
let present age of Aftab be x
let present age of his daughter be y
7 YEARS AGO
(aftab's present age) - 7 = 7 x [(his daughter's present age) - 7]
x-7 = 7 x (y-7)
x-7 = 7y - 49
x-7y = -42 ---------------------- [1]
3 YEARS LATER
(aftab's present age) + 3 = 3[(his daughter's present age) +3]
x+3 = 3 x (y+3)
x+3 = 3y + 9
x-3y = 6 ---------------------- [2]
from [2],
x = 6 + 3y ---------------------- [3]
putting [3] in [1],
x-7y = -42
6+3y-7y = -42
6-4y = -42
-4y = -42-6
-4y = -48
y = -48/-4
y = 12
putting y=12 in [2],
x = 6+3y
x = 6+36
x = 42
therefore, the present ages of aftab and his daughter are 42years and 12 years respectively.
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