Math, asked by Gamingplanet, 8 months ago

Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” (Isn’t this interesting?) Represent this situation algebraically and graphically.

Answers

Answered by Jay0805
3

Answer:

Step-by-step explanation:

let present age of Aftab be x

let present age of his daughter be y

7 YEARS AGO

(aftab's present age) - 7 = 7 x [(his daughter's present age) - 7]

x-7 = 7 x (y-7)

x-7 = 7y - 49

x-7y = -42   ----------------------  [1]

3 YEARS LATER

(aftab's present age) + 3 = 3[(his daughter's present age) +3]

x+3 = 3 x (y+3)

x+3 = 3y + 9

x-3y = 6   ----------------------  [2]

from [2],

x = 6 + 3y   ----------------------  [3]

putting [3] in [1],

x-7y = -42

6+3y-7y = -42

6-4y = -42

-4y = -42-6

-4y = -48

y = -48/-4

y = 12

putting y=12 in [2],

x = 6+3y

x = 6+36

x = 42

therefore, the present ages of aftab and his daughter are 42years and 12 years respectively.

hope it helps!!!

Answered by Ritu92005
5

It helpful for you Make me brainlest☺☺

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