Aftab tells his daughter, "Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be." (Isn't this interesting?) Represent this situation algebraically and graphically.
Answers
Answer:
Acc. to 1st condition
x- 7y = -42
Acc to 2nd condition
x- 3y = 6
Step-by-step explanation:
Hey mate..,......
Consider Aftab's age as x and his daughter's age as y.
Then , seven years ago,
Aftab's age =x−7
His daughter's age =y−7
According to the question,
x−7=7(y−7)
x−7=7y−49
x−7y=−49+7
x−7y=−42 …(i)
x−7y=−42 …(i)
After three years,
Aftab's age =x+3
His daughter's age =y+3
According to the question,
x+3=3(y+3)
x+3=3y+9
x−3y=9−3
x−3y=6 …(ii)
Representing equation (i) and (ii) geometrically, we plot these equations by finding points on the lines representing these two equationsx−7y=−42
⟹x=7y−42
x=7y−42
x−3y=6
⟹x=3y+6
From the graph we can see that two lines will intersect at a point.
x−7y=−42
x−3y=6
On subtracting the two equations, we get 4y=48
or y=12
Substituting value of y in (2),
x−36=6
∴x=42
HOPE IT HELPS YOU
