Aftab tells his daughter "seven years ago, I was seven times as old as you were then also three years from now, I shall be three times as old as you find the present age of aftab& his daughter (x &y). (Hint: Aftab age is x & daughter age is y)
Answers
Answered by
29
Solution :-
Let :-
Present age of Aftab = x
Present age of daughter = y
Seven years ago :-
Age of Aftab = x - 7
Age of daughter = y - 7
After three years :-
Age of Aftab = x + 3
Age of daughter = y + 3
According to the first condition :-
According to the second condition :-
Equation (2) - Equation (1) :-
Substitute the value of y in eq (2) :-
Present age of Aftab = 42 years
Present age of daughter = 12 years
Answered by
52
Step-by-step explanation:
Let
the present age of Aftab=x
the present age of daughter=y
Seven years ago :-
the age of father=x-7
the age of daughter=y-7
After 3 years :-
the age of father=x+3
the age of daughter=y+3
According to the first condition,
According to the second condition:-
Equation(2)-Equation(1):-
Substitute the value of y in Equation(1):-
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