Question

After 10 years the age of x is twice the age of y before 10 years the age of x is sixth times the age of y find t
heir ages

Answer 1

Answer:

Let's take age of y=y

Before 10 years,

Age of y= y

Age of x=6y

Now,,

Age of y =y+10

Age of x=6y+10

After 10 years,,

Age of y= y+20

Age of x=6y+20

2(y+20)=6y+20

2y+40=6y+20

2y+20=6y

20=6y-2y=4y

20/4=y

y=5

Age of y now = 5+10 =15

Age of x now =6*5+10=30+10=40

Hope this will help...

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