after 15 years hema's will begin for four times that her present age find her
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HEYA...
ANSWER..
let her present age be X yrs.
after 15 yrs her age would be =4X
ATQ―»
X+15=4X
―» 4X-X=15
―» X = 5 yrs...
hope it's helpful....
ANSWER..
let her present age be X yrs.
after 15 yrs her age would be =4X
ATQ―»
X+15=4X
―» 4X-X=15
―» X = 5 yrs...
hope it's helpful....
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