Math, asked by karthikadi2356, 8 months ago

After 15 years, Mary's age will be four times of her present age.
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Answers

Answered by narendras1232
0

Answer:

Let Mary's age be x

15+x = 4x

15 = 4x-x

15 = 3x

15/3 = x

5 = x

her present age is 5 I will follow you if you mark me as brainliest

Answered by ItzAditt007
2

AnswEr:-

Given:-

  • After 15 years Mary's age will be four times of her present age.

To Find:-

  • The present age of Mary.

So let the present age of Mary be x years.

Therefore,

After 15 years her age will be (x+15) years.

Also 4 times of her present age will be 4x years.

So ATQ:-

 \\ \tt\mapsto x + 15= 4x \: years. \\  \\ \tt\mapsto4x  - x  = 15  . \\  \\ \tt\mapsto3x = 15  . \\  \\ \tt\mapsto \: x =\cancel  \frac{15}{3} \\  \\  \tt\mapsto x = 5.

Therefore Mary's present age is x = 5 years.

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