After 4 years, Tenzin will be 24 years old and his father will become twice as old as himself. Two years before, his mother’s age was twice his age. What is the age for his father and mother?
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Answer:
Let son's age = x
Two years ago son's age= x-2.
His Father's age at that time = 3(x-2).
Present age of Father = 3x-6+2=3x-4
Two years hence father's age=3x-4+2=3x-2.
Two years hence son's age = x+2.
Given :-5*(x+2)=2*(3x-2)
5x + 10= 6x - 4
10+4=6x-5x
14=x
SON'S PRESENT AGE : 14 years.
FATHER'S PTESENT AGE: 38 years.
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After 4 years, Tenzin will be 24 years old and his father will become twice as old as himself. Two years before, his mother’s age was twice his age. What is the age for his father and mother?
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