after 5 year the age of a father will be three times of the age of his son . 5 years ago he was 7 times as old as his son was . what was present ages
Answers
AnswEr :
Let the Present Age of Father be n yrs and Present Age of Son be m yrs.
• According to the Question Now :
⋆ After 5 year the age of a father will be three times of the age of his son.
⇝ Father = 3 times of Son
⇝ (n + 5) = 3 × (m + 5)
⇝ n + 5 = 3m + 15
⇝ n = 3m + 15 - 5
⇝ n = 3m + 10 —eq. ( I )
⋆ 5 years ago he was 7 times as old as his son was.
⇝ Father = 7 times of Son
⇝ (n - 5) = 7 × (m - 5)
⇝ (3m + 10 - 5) = 7 × (m - 5) —[ from I ]
⇝ 3m + 5 = 7m - 35
⇝ 35 + 5 = 7m - 3m
⇝ 40 = 4m
- Dividing Both term by 4
⇝ m = 10 Yrs. [ Son Present Age ]
• Putting the Value of m in ( I )
⇝ n = 3m + 10
⇝ n = 3 × 10 + 10
⇝ n = 30 + 10
⇝ n = 40 Yrs. [ Father Present Age ]
∴ Hence, Present Age of Father is 40 Years and Present Age of Son is 10 Years.
Answer:
Step-by-step explanation:
Let,
The present age of Father is 'x' yrs.
And,
The present age of son is 'y' yrs.
Now,
After 5 Years
Age Of father = (x+5) yrs.
And,
Age of son = (y+5) yrs.
But,
According to question,
Father will be 3 times of the age of his son.
Therefore,
We have the following equation,
Now,
Before 5 Years,
Age of father = (x-5) yrs.
And,
Age of son = (y-5) yrs.
But,
According to Question,
Father would be 7 times the age of his son.
Therefore,
We have the following Equation,
Now,
Subtracting eqn (i) from (ii),
We get,
Now,
Putting this value of y = 10, in eqn (ii),
We get,
Hence,
Present age of father = 40 yrs.
Present age of his son = 10 yrs.