After 5 years, John will be 24 years old and his father will become twice as old as himself. 3 years before, his mother’s age was 2 times his age. Age difference between his father and mother is?
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Two years ago, father was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Find their presents ages.
Step-by-step explanation:
Let son's age = x
Two years ago son's age= x-2.
His Father's age at that time = 3(x-2).
Present age of Father = 3x-6+2=3x-4
Two years hence father's age=3x-4+2=3x-2.
Two years hence son's age = x+2.
Given :-5*(x+2)=2*(3x-2)
5x + 10= 6x - 4
10+4=6x-5x
14=x
SON'S PRESENT AGE : 14 years.
FATHER'S PRESENT AGE: 38 years.
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