after 5 years, the age of a father will be triple the age of his son, while 5 years ago he was 7 times as old as his son was. find their present ages.
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Answer:
Five years hence, a man's age will be three times the age of his son. Five years ago, the man was seven times as old as his son. And His son's be y years. Hence, man's present age = 40 years and son's present age = 10 years.
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Let Five years ago the age of son be x years and age of father be 7x years
Present age of son =x+5
Present age of father =7x+5
5 years later their age will (x+10) and (7x+10)
∴7x+10=3(x+10)
7x−3x=20
4x=20
x=5
So, the present age of son=x+5=5+5=10years
and the present age of father=7x+5=35+5=40years
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