Question

After 6 years raju's father's age will be twice that of his age and 2 years ago, his mother's age was twice that of raju's age. What is the sum of raju's parents' age?

Answer 1

Let present agree of Raju's Father be f

Present age of Raju be r

& present age of Raju's Mother be m

•• After 6 years,

Raju's Fathers age = f+6

& Raju's age = r+6

Given,

Raju's Father age = 2(Raju's age)

=> (f+6) = 2(r+6)

=> f = 2r + 6

•• Two years ago, ft

Raju's mothers age = m-2

& Raju's age = r-2

Given,

Raju's Mother's age = 2×( Raju's age)

=> m-2 = 2(r-2)

=> m = 2r - 2

Sum of Raju's parent' s age is

=> f+m = 2r+6+2r-2

=> f+m = 4r+4

i. e., 4 more than 4times the Raju's present age.

•°• Sum of Raju's parent' s age is 4 more than 4times the Raju's age

Hope it helps