After 6 years raju's father's age will be twice that of the his age and2 years ago, his mothers age was twice that of raju's age. What isthe sum of raju's parents' age
Answers
Answered by
8
Hi there!
Here's the answer:
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•°
Let present agree of Raju's Father be f
Present age of Raju be r
& present age of Raju's Mother be m
•• After 6 years,
Raju's Fathers age = f+6
& Raju's age = r+6
Given,
Raju's Father age = 2(Raju's age)
=> (f+6) = 2(r+6)
=> f = 2r + 6
•• Two years ago,
Raju's mothers age = m-2
& Raju's age = r-2
Given,
Raju's Mother's age = 2×( Raju's age)
=> m-2 = 2(r-2)
=> m = 2r - 2
Sum of Raju's parent' s age is
=> f+m = 2r+6+2r-2
=> f+m = 4r+4
i. e., 4 more than 4times the Raju's present age.
•°• Sum of Raju's parent' s age is 4 more than 4times the Raju's present age.
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•°
Hope it helps
Here's the answer:
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•°
Let present agree of Raju's Father be f
Present age of Raju be r
& present age of Raju's Mother be m
•• After 6 years,
Raju's Fathers age = f+6
& Raju's age = r+6
Given,
Raju's Father age = 2(Raju's age)
=> (f+6) = 2(r+6)
=> f = 2r + 6
•• Two years ago,
Raju's mothers age = m-2
& Raju's age = r-2
Given,
Raju's Mother's age = 2×( Raju's age)
=> m-2 = 2(r-2)
=> m = 2r - 2
Sum of Raju's parent' s age is
=> f+m = 2r+6+2r-2
=> f+m = 4r+4
i. e., 4 more than 4times the Raju's present age.
•°• Sum of Raju's parent' s age is 4 more than 4times the Raju's present age.
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•°
Hope it helps
Answered by
1
Answer:
the sum of the present age is 4 more than the 4 times the Raju's age
Attachments:
Similar questions
Computer Science,
7 months ago
Biology,
7 months ago
Physics,
7 months ago
Business Studies,
1 year ago
Physics,
1 year ago
Math,
1 year ago
History,
1 year ago
Math,
1 year ago