Math, asked by yashikarao6022, 1 year ago

After 6 years raju's father's age will be twice that of the his age and2 years ago, his mothers age was twice that of raju's age. What isthe sum of raju's parents' age

Answers

Answered by VemugantiRahul
8
Hi there!
Here's the answer:

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Let present agree of Raju's Father be f
Present age of Raju be r
& present age of Raju's Mother be m


•• After 6 years,
Raju's Fathers age = f+6
& Raju's age = r+6

Given,
Raju's Father age = 2(Raju's age)
=> (f+6) = 2(r+6)
=> f = 2r + 6


•• Two years ago,
Raju's mothers age = m-2
& Raju's age = r-2

Given,
Raju's Mother's age = 2×( Raju's age)
=> m-2 = 2(r-2)
=> m = 2r - 2



Sum of Raju's parent' s age is
=> f+m = 2r+6+2r-2
=> f+m = 4r+4
i. e., 4 more than 4times the Raju's present age.


•°• Sum of Raju's parent' s age is 4 more than 4times the Raju's present age.

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Hope it helps
Answered by vihaspoojari8
1

Answer:

the sum of the present age is 4 more than the 4 times the Raju's age

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