After 6 years , Rema's age will be 4 times Beena's age . After 10 years , it will just be 3
times .a}what are thier ages now
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Let Rama’s age be ‘x’ and Beena’s age be ‘y’
After 6 years:
(x+6) = 4(y+6)
x = 4y + 24 - 6
∴ x = 4y + 18____(1)
After 10 years:
(x+10) = 3(y+10)
x+10 = 3y+30_____(2)
On substituting (1) in (2):
4y + 18 + 10 = 3y + 30
y = 2
And hence, x = 26
∴ Rama’s present age is 26 years and Beena’s present age is 2 years.
After 6 years:
(x+6) = 4(y+6)
x = 4y + 24 - 6
∴ x = 4y + 18____(1)
After 10 years:
(x+10) = 3(y+10)
x+10 = 3y+30_____(2)
On substituting (1) in (2):
4y + 18 + 10 = 3y + 30
y = 2
And hence, x = 26
∴ Rama’s present age is 26 years and Beena’s present age is 2 years.
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