After 7 years, 3 times of age of Saif will be equal to his father's age which is equal to 6 times Saif's Present age.Find the present ages of both of them
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As from the question, we consider father’s age is F and children’s age is C.
Let’s go to find the father’s age.
Initial equation is,
F = 3 C ————————— >>> (A)
After 5 years, the equation will be,
(F+5) = (3C+15)
(here 15 is the total of age increased for each children)
But, after 5 years father’s age is 6/7. So,
(F+5) = (3C+15) x 6/7
to be clear,
(F+5) = [(3C+15) x 6] / 7
7 x (F+5) = (3C+15) x 6
this is turned to following equation as per (A)
7 x (F+5) = (F+15) x 6
now, multiplied equation is,
7F + 35 = 6F + 90
rearranging into the following,
7F - 6F = 90 - 35
simply,
F = 55.
So,
The father is 55 years old now.
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