After 7 years, three times the age of lalit will be equal to his father's age which is equal to 6times lalit's present age. Find the present ages of both of them.
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let present age of Lalit and his father be X and Y respectively
ATQ
3(X+7)=Y+7
Also
6X=3(X+7)
6X=3X+21
3X=21
X=7 years(Lalit)
Now
3(7+7)=y+7
42=y+7
y=35 years(his father)
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Answered by
1
Answer:
Let the age of Lalit be x
And age of his father be y
According to the condition,
7 years after,
3(x + 7) = y
3x + 21= y
3x - y =21 __1
6(x+7) = y
6x +42= y
6x - y= 42 ___2
Substitute the value of in eq 2
X = 21 + y/3
6x - y= 42
6( 21+y / 3 )- y = 42
126+ 6y - 3y= 42
3 y = 126- 42
Y= 84 ÷3
Y =26
Step-by-step explanation:. Hence the age of Lalit be years and age of his father be 26 years .
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