Math, asked by vistoworry, 3 months ago

after 8 minutes in a batch reactor ​

Answers

Answered by Anonymous
1

Answer:

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Answered by shifarahman2008
0

Answer:

Given initial concentration Cao = 1 mole/lit Also given at t1 = 8 min, conversion X1 =0.8 therefore final concentration Ca1 = Ca0(1-X1) = 1 ( 1- 0.8) = 0.2 Ca1= 0.2 mole/lit and t2= 18 min, conversion X2 =0 .9 therefore final concentration Ca2 = Ca0(1-X2) = 1 ( 1- 0.9) = 0.1 Ca2= 0.1 mole/lit Now we will find the reaction rate constant values for different order reactions for given two datas and compare Let assume the reaction is zero order reaction ie -ra = K where K is reaction rate constant ra = dCa/dt substituting in above equation and integrating we get Ca1 = (-Kt) + Ca0 K= Ca0-Ca1/t1 0.9750 mole/lit-min and also K= Ca0-Ca2/t2 0.9944 mole/lit-min Let assume the reaction is first order reaction ie -ra = Kca where K is reaction rate constant ra = dCa/dt substituting in above equation

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