Math, asked by EMR, 1 year ago

After 8 years Raj will be 3 times as old as he was 2 years ago. His present age is
(A) 7 yrs (B) 9 yrs(C) 10 yrs (D) 11 yrs


Anonymous: the answer is 7 years
Anonymous: please see the explanation :
Anonymous: let the present age of Raj = x , after 8 years Age of Raj = x+8 , before two years , Age of Raj = x-2 , therefore according to problem , x+8 = 3(x-2) => x+8 = 3x - 6 => x+8 +6 = 3x => x+14 = 3x => 3x-x = 14 => 2x=14 => x=14/2 => x=7 ..hence age of raj = 7 years
chandu1711: 7 years

Answers

Answered by kopal
26
answer to ur question is a) 7.
solution :- let raj's present age be x 
then equation = (x+8)=3(x-2)
=x+8 = 3x-6
=x-3x= -6-8
= -2x = -14 
both the minus signs are cut because they are similiar
= 2x=14
= x=14/2
=x=7.
so therefore raj's present age is 7yrs.
hope this helps u !!!!!!!


Answered by Anonymous
8
et the present age of Raj = x , after 8 years Age of Raj = x+8 , before two years , Age of Raj = x-2 , therefore according to problem , x+8 = 3(x-2) => x+8 = 3x - 6 => x+8 +6 = 3x => x+14 = 3x => 3x-x = 14 => 2x=14 => x=14/2 => x=7 ..hence age of raj = 7 years
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