after a batsmane hit, the ball travelled 70 3/4 m, in the next hit the ball travelled 90 1/5 m. how much further did the second ball travel than the first?
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Answer: 19 9/20 m (19.45 m)
Step-by-step explanation:
Distance travelled by the first ball = 70 3/4 m
Distance travelled by the second ball = 90 1/5 m
To find:
Distance travelled more by the second ball =
Method 1 :
90 1/5 - 70 3/4
= (90 - 70) + (1/5 - 3/4)
= 20 + (1/5 x 4/4 - 3/4 x 5/5)
= 20 + (4/20 - 15/20)
= 20 + (-11/20)
= 20 - 11/20
= 20 x 20/20 - 11/20
= 400/20 - 11 / 20
= 389/20
= 19 9/20
OR
Method 2 :
90 1/5 - 70 3/4
= 451/5 - 283/4
= 451/5 x 4/4 - 283/4 x 5/5
= 1804/20 - 1415/20
= 389/20
= 19 9/20
OR
Method 3 :
90 1/5 - 70 3/4
= 90.2 - 70.75
= 19.45
∴ The second ball travelled 19 9/20 m (19.45 m) more than the first ball.
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