After absorbing 1.94 x 10 -18 J of energy, find the orbit, to which electron in the ground state of hydrogen atom jumps. Find the wavelength of radiation emitted when it comes back to the ground state. please answer fast.
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Answer:
The electron in the ground state of H-atom jumps to the nth state after absorbing the radiation.
Wavelength of the radiation, λ=970A
o
=970×10
−10
m
Energy gained by the electron, E
′
=
eλ
hc
eV=
970×10
−10
1.237×10
−6
=12.75eV
Thus the energy of the n
th
state, E
n
=−13.6+12.75=−0.85eV
Using: E
n
=
n
2
−13.6
eV
∴ −0.85=
n
2
−13.6
⟹n=4
Number of (emission) spectral line, N=
2
n(n−1)
=
2
4(4−1)
=6 lines
The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is
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