After all the faces of a cube are painted, the cube is cut into 64 small cubes of equal dimensions. How many small cubes have
(i) no face painted?
(ii) 1 face painted?
(iii) 2 faces painted?
(iv) 3 faces painted?
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Answer:
For a cube of side n*n*n painted on all sides which is uniformly cut into smaller cubes of dimension 1*1*1,
Number of cubes with 0 side painted = (n-2)3
Number of cubes with 1 side painted = 6(n - 2)2
Number of cubes with 2 sides painted = 12(n-2)
Number of cubes with 3 sides painted = 8 (always)
Given, the cube is separated into 64 small cubes.
So, n3 = 64
⇒ n = 4
By formula:
Number of cubes with no side painted = (n - 2)3
= (4 - 2)3
= 23
= 8
Hence, ‘8’ is the correct answer.
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