Question

After allowing two successive discounts of 20 % and 25 % , a watch sold for Rs. 6000. What is the marked price of the watch.​

Answer 1

Answer:

9600

Step-by-step explanation:

please mark as brainliest

Answer 2

$\sf \: Here \: Selling \: price \: = \: Rs. \: 6000.$

$\sf \: Let \: the \: Marked \: price \: of \: a \: watch \: = \: Rs. \: x$

$\sf \: First \: discount \: = \: 20 \: \% \: of \: Rs. \: x$

$\sf \: = \dfrac{20}{100} \: x \: = \: Rs. \: \dfrac{x}{5}$

$\sf \: Price \: after \: discount \: = \: Rs. \bigg( \: x \: - \: \dfrac{x}{5} \bigg) \: = \: Rs. \: \dfrac{ 4x}{5}$

$\sf \: Second \: discount \: = \: 25 \: \% \: of \: Rs. \: \dfrac{4x}{5}$

$\sf \: = \: \dfrac{25}{100} \: \times \: Rs. \: \dfrac{4x}{5} \: = \: Rs. \: \dfrac{x}{5}$

$\sf \: Price \: after \: second \: discount \: = \: Rs. \: \bigg( \: \dfrac{4x}{5} - \dfrac{x}{5} \bigg) \: = \: Rs. \: \dfrac{3x}{5}$

$\sf \: Therefore \: selling \: price \: = \: \dfrac{3x}{5}$

$\sf \: Rs. \: 6000 \: = \: \dfrac{3x}{5}$

$\sf \: x \: = \: \dfrac{6000 \: \times \: 5}{3}$

$\sf \: x \: = \: Rs. \: 10,000$

$\sf \: Hence, \: the \: Marked \: price \: of \: the \: watch\: is \: Rs. \:10,000$

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$\sf \: Alternative \: Method \: : \:$ ↴

$\sf Here \: d_1 = 20 \: \%, \: d_2 = 25 \: \%$

$\sf \: Also \: SP \: = \: Rs. \: 6000$

$\sf \: SP \: after \: two \: discount \: = \: \bigg( 1 \: + \: \dfrac{d_1}{100} \bigg) \: \bigg( \: 1 \: + \: \dfrac{d_2 }{100} \bigg) \: \times \: MP$

$\sf \: Rs. \: 6000 \: = \: \bigg( \: 1 \: - \: \dfrac{20}{100} \bigg) \: \bigg( \: 1 \: - \: \dfrac{25}{100} \bigg) \: \times \: Rs. \: x$

$\sf \: 6000 \: = \: \dfrac{80}{100} \: \times \: \: \dfrac{75}{100} \: \times \: x$

$\sf \: x \: = \: \dfrac{6000 \: \times \: 100 \: 100}{8 \: \times \: 75} \: = \: Rs. \: 1000$

$\sf \: Hence \: the \: marked \: price \: = \: Rs. \: 10,000$