After angleABD = angle CBD
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2) angle a = angle b
a+x= 180° ( linear pair ) -1
b+y= 180° ( linear pair ) -2
a+x=b+y
a=b
a+x=a+y
a+x-a=y
x=y (alternate angles)
therefore, l||m
3) AB = 8cm
AM = BM ( M is the mid-point)
AB = AM + BM
AB= AM + AM
8= 2AM
8/2= AM
4= AM
therefore, AM = 4cm
4) From ∆ABD and ∆CBD
AD= CD ( Given )
AB= BC ( Given )
BD= BD. (Common)
therefore, ∆ ABD is = ∆CBD
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