Question

After collision block B moves with
velocity of 5m/s in same direction
Find out velocity of block A.
​

Answer 1

Answer:

Given,

Mass=m,Velocity=5m/s,d=2m,μ=0.25,g=10m/s

2

So for the mass 1,

V

in

=5m/s Let the final velocity that is imparted to the other mass before the collision be V

f

So Acceleration =μ×g=0.25×10=2.5⇒a=−2.5m/s

2

(negative sign shows friction acts opposite to the direction of motion)

Now, V

f

2

=V

in

2

+2as⇒V

f

2

=25−2×2.5×2=15⇒V

f

=

15

m/s

At the time of collision, momentum will be conserved. So the velocity of both mass will exchange.

For the second mass,

Velocity gained V

f

=

15

m.s= to the initial velocity of the second mass= u

Now, A/C to the question the mass cofinal velocity of the second mass to rest sov=0

Thus, By the kinematic equations

V

2

=U

2

+2as⇒==(

15

)

2

+2×(−2.5)×s⇒s=

5

15

=3m