Question

after correcting 50 pages of the proof of a book the proof reader finds there are on an average 2 errors per 5 pages. how many errors will one expect to find with 1, 2, 3, 4 errors in 1000 pages​

Answer 1

Given : after correcting 50 pages of the proof of a book the proof reader finds there are on an average 2 errors per 5 pages.

To Find :  how many pages will one expect to find with 1, 2, 3, 4 errors in 1000 pages​

Solution:

Poisson distribution

P(x)  = { λˣ  e^(-λ) } / x!

2 errors per 5 pages. => 2/5  = 0.4   errors  per  pages

λ  = Mean  = 0.4

P(1)  =   { (0.4)¹  e^(-0.4) } / 1!   =  0.2681

P(2)  =   { (0.4)²  e^(-0.4) } / 2!   = 0.0536

P(3)  =   { (0.4)³  e^(-0.4) } / 3!   = 0.0071

P(4)  =   { (0.4)⁴  e^(-0.4) } / 4!   = 0.0007

1 errors    in 1000 pages = 1000 * 0.2681  =  268

2 errors    in 1000 pages = 1000 * 0.0536  =  54

3 errors     in 1000 pages = 1000 * 0.0071 =   7

4 errors     in 1000 pages = 1000 * 0.0007  =   1

Learn More

A car hire firm has 2 cars which is hired out everyday. The number of ...

brainly.in/question/19982036

The number of traffic accidents that occur on a particular stretch of ...

brainly.in/question/15583001

Answer 2

P=3/5
n=50
Lemda = np =10