after covering 2/3 of the distance of 528 km the speed of a car is reduced by 5/11 of its initial speed and it takes 1 hour 40 min more time to cover the total distance what is its initial speed?
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time taken to travel the first 2/3 rd distance + time taken for the last 1/3rd distance
= time taken to travel entire distance with initial speed + 100 minutes
let the initial speed be v kmph
(2*528 / 3v) + (528/3) / (6v/11) = 528/v + 100/60
solving the above, you will get v = 88 km/hr
= time taken to travel entire distance with initial speed + 100 minutes
let the initial speed be v kmph
(2*528 / 3v) + (528/3) / (6v/11) = 528/v + 100/60
solving the above, you will get v = 88 km/hr
Answered by
0
Answer:
88km/h
Hope it helps you brother
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