Question

after covering a distance of 30 kilometre with uniform speed there is some defect in the train engine and therefore its speed reduced to 4 by 5 of its original speed consequently the train reaches its destination late by 45 minutes. had it happened after covering 18 kilometre more the train would have reached nine minutes earlier. find the speed of train and distance of journey .




please clearely answer guys..​

Answer 1

Answer:

speed of train=30km/h

distance=120km

Step-by-step explanation:

let "x" be the speed of train

"y" he the distance travelled

Case 1

$30 \div x + y - 30 \div 4 \div 5x = y \div x + 45$

case 2

$y \div x - 36 \div 60 = 48 \div x + y - 48 \div 4 \div 5 \times x$