Question

After covering a distance of 30 km,there is some defect in a train engine and there after,its speed is reduced to 4/5 of its original speed.Consequently, the train reaches its destination late by 45 minutes.Had it happened after covering 18 km more,the train would have reached 9 minutes earlier.Find the speed of the train and the distance of journey.

Answer 1

Train proceeds at 4/5 S where S is his usual speed means 1/5 decrease in speed which

Now the main difference comes in those extra 

18km  and the change in difference of time = (45-36) min = 9 min.

Thus,

1/4*T = 9 min where T is the time required to cover the distance of 18 km.

T = 36 min = 36 /60 hours = 0.6 hours.

Speed of the Train =  18/0.6 = 30 kmph.

Distance =4/5×150=120KM

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