Question

After firing a bullet is found to move at an angle of 37 degree to horizontal its acceleration is 10 m per second square downwards find
the component of acceleration in the direction of velocity.

Answer 1

Answer:

The vector makes 37° with X axis in downward direction.

Explanation:

Let the component at X-axis be a(vector) and at y-axis be b(vector).

Then,

a = - 10cos37° i

b = - 10sin37° j

These, are the components

of the vector bullet.

Mark it as brainlist.