Question

after heating x gram of sodium bicarbonate 5.6 litre of co2 is liberated at STP then the value of x is
​

Answer 1

Answer:

The reaction is CaCO

3

→CaO+CO

2

.

One mole of calcium carbonate forms one mole of carbon dioxide.

At STP, 5.6 L of carbon dioxide corresponds to 0.25 moles.

They will be obtained from 0.25 moles of calcium carbonate.

Molar mass of CaCO

3

=100g

0.25 moles of calcium carbonate (molecular weight 100 g/mole) corresponds to 25 g.