After how many decimal place will the decimal expansion of the rational no 4t/2^3 5^2 terminate.
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0
Answer:
two decimal places
Step-by-step explanation:
After how many decimal place will the decimal expansion of the rational no 4t/2^3 5^2 terminate.
4t/(2³ * 5²)
= 2t/(2² * 5²)
= 2t/((2 * 5)²)
= 2t/(10²)
= 2t/100
= 0.02t
after two decimal places it terminates
Answered by
0
Answer:
4t/(2³ * 5²)
= 2t/(2² * 5²)
= 2t/((2 * 5)²)
= 2t/(10²)
= 2t/100
= 0.02t
Hence the answer is : after two decimal places it terminates
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