Math, asked by shsshivkumar, 7 months ago

after how many decimal places the rational number 13/2^4×5^3 will terminate​

Answers

Answered by gana247
31

Answer:

13/2^4 x 5^3 will terminate after 4 decimal places.

Step-by-step explanation:

13/2^4 x 5^3

= 13 x 5^3 / 2^4

Multiply numerator and denominator by 5^4

= 13 x 5^3 x 5^4 / 2^4 x 5^4

= 13 x 5^3 x 5^4 / 10^4

= 1,015,625 / 10^4

= 101.5625

Thus, it will terminate after 4 decimal places.

Answered by pulakmath007
3

SOLUTION

TO DETERMINE

After how many decimal places the below rational number will terminate

\displaystyle \sf{   \frac{13}{ {2}^{4} \times  {5}^{3}  }  }

CONCEPT TO BE IMPLEMENTED

\displaystyle\sf{Fraction =  \frac{Numerator}{Denominator} }

A fraction is said to be terminating if prime factorisation of the denominator contains only prime factors 2 and 5

If the denominator is of the form

 \sf{Denominator =  {2}^{m}  \times  {5}^{n} }

Then the fraction terminates after N decimal places

Where N = max { m , n }

EVALUATION

Here the given rational number is

\displaystyle \sf{   \frac{13}{ {2}^{4} \times  {5}^{3}  }  }

Numerator = 13

Denominator = 2⁴ × 5³

Since the prime factorisation of the denominator contains only prime factors as 2 and 5

So the given rational number is terminating

The exponent of 2 = 4

The exponent of 5 = 3

Max{ 4 , 3 } = 4

Hence the given rational number terminates after 4 decimal places

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