After how many decimal places will 229/2²*5to the power 7 terminates
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Step-by-step explanation:
First we have to make the base a power of 10 , that is we know 5 * 2 is 10 so we have to make the powers of exponets of 2 and 5 in the denominator same so we multiply 2^5 on both numerator and denominator
229/2^2*5^7 * 2^5/2^5
which becomes
->229*2^5/2^(2+5)*5^7
here in the denominator as 2 and 5 have the same powers we can take 2 and 5 common into (2*5)^7 -> 10^7
Here as base is 10 followed by 7 zeroes , the decimal will terminate after 7 places
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