after how many seconds is need for a throw ball to reach a 14-m distance if it's distance is given by the relation d=10 + 40t - 5+²? (t= time in seconds)
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Answered by
8
Answer:
velocity after 2 sec.
v=40+(−10)t
=40−10∗2=20m/s
Answered by
6
Answer:
velocity after 2sec
v=40+(-10t)
=40-10 2=20m/s
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