Question

After how much time energy becomes 1/e of the maximum value in r l circuit where r=2 ohm and l=2mili henry

Answer 1

Answer:

Energy becomes 1/e times of maximum energy after t = 0.5 ms

Explanation:

As we know that current in RL circuit is given as

$i = i_o e^{-Rt/L}$

now we know that energy stored in the inductor is given as

$U = \frac{1}{2}Li^2$

$U = \frac{1}{2}Li_o^2 e^{-2Rt/L}$

so we can say

$U = U_{max} e^{-2Rt/L}$

now we have to find the time after which energy becomes 1/e times maximum energy

$\frac{U_{max}}{e} = U_{max} e^{-2Rt/L}$

so we have

$t = \frac{L}{2R}$

now plug in all data

$t = \frac{2 \times 10^{-3}}{2(2)}$

$t = 0.5 ms$

#Learn

Topic : LR circuits

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