Question

After how much time energy becomes 1/e of the maximum value in a R-L circuit where R = 2 ohm and L= 2 mH

Answer 1

Answer:

After $t = 9.3 \times 10^{-4} s$ energy becomes 1/e of the maximum value in a R-L circuit.

Explanation:

As we know that in R-L circuits we have current in the circuit is given as

$i = \frac{V}{R}(1 - e^{-Rt/L})$

so here energy stored in the inductor is given as

$E = \frac{1}{2}Li^2$

now energy becomes 1/e times of total energy

so we have

$\frac{1}{e} = (1 - e^{-Rt/L})^2$

here we know that

$e^{-0.5} = 1 - e^{-1000 t}$

so we have

$t = 9.3 \times 10^{-4} s$

#Learn

Topic : LR circuit

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