after landing on a unfamiliar planet, a sphere explorer construct a simple pendulum of length 50cm.she finds that pendulum makes 100 complete swings in 136 second.what is the value of g on this planet?
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Answer:
Explanation:
Given, l = 50 cm = 0.5 m
T = 2π √(L / g) , where
L = length of spring
g = acceleration due to gravity
T = period
T can also be gotten using the formula,
T = total number of oscillations / time taken, so that
T = 136 / 100
T = 1.36
T = 2π √(L / g)
1.36 = 2 * π * √(0.5 / g)
1.36 = 6.284 * √(0.5 / g)
1.36² = 6.284² * (0.5 / g)
1.85 = 39.49 * 0.5 / g
g = 19.745 / 1.85
g = 10.67 m/s²
Thus, we can infer that the value of g on this planet is 10.67 m/s²
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