After painting his porch, Jamil has 1/4 of a can of paint remaining. The can has a radius of 8 cm and a height of 20 cm. He wants to pour the remaining paint into a smaller can for storage. The smaller can has a radius of 5 cm. What does the height of the smaller can need to be to hold all of the paint?
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Given: Can has a radius of 8 cm and a height of 20 cm, smaller can has a radius of 5 cm.
To find: What is the height of the smaller can to hold 1/4 of the paint?
Solution:
- As we have given that the original can is having 1/4 th of paint remaining. So lets find the volume of the can:
- Volume of cylinder(can) = πr²h
V = 22/7 x 8² x 20
V = 22/7 x 64 x 20
V = 22/7 x 1280
V = 4022.85 cm²
- Now 1/4 th of the paint is remaining, so:
4022.85 x 1/4 = 1005.71 of paint is remaining.
- Now this paint should be equal to volume of small can
- Volume of small can is
22/7 x (5)² x h = 1005.71
h = 1005.71 x 7 / 22 x 25
h = 7,039.97 / 550
h = 12.79 cm (approx)
Answer:
The height of the smaller can need to be to hold all of the paint is 12.79 cm (approx)
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1
Answer:
12.8
Step-by-step explanation:
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