Question

After putting the value of x = 3 in P(x) = k * x ^ 3 + 4x ^ 2 + 3x - 4 , we get
a) 27k
b) 27k + 41
c) 41
d) 9k + 41​

Answer 1

Answer:

C is the ans

Step-by-step explanation:

P(3)=K*X^3+4X^2+3X-4

P(3)=K*(3)^3 +4*(3)^2+3*3-4

P(3)=K*27+36+9-4

P(3)=K*27+36+5

P(3)=K*27+41

P(3)=27K+41

Answer 2

Given:

$P(x)= kx^{3}+4x^{2} +3x - 4$

To Find:

Find the value of $P(x)$ when $x= 3$.

Solution:

Given that, $P(x)= kx^{3}+4x^{2} +3x - 4$

Now putting x = 3 we get,

$P(3)= k(3)^{3}+4(3)^{2} +3(3) - 4 = 27k+36+9-4 = 27k+41$

Therefore, $P(3)=27k+41$