Question

After rationalising the denominator of 7/(3√3 - 2√2), we get the denominator as (a) 13 (b) 19 (c) 5 (d) 35

Answer 1

Answer:

Step-by-step explanation:

we get 27 - 8 = 19

Answer 2

We have to find only denominator.

so let numerator be n

$= \frac{7}{3\sqrt{3} - 2 \sqrt{2} } \times \frac{3 \sqrt{3 } + 2 \sqrt{2} }{3 \sqrt{3} + 2 \sqrt{2} } \\ = \frac{7(3 \sqrt{3} + 2 \sqrt{2} )}{ {(3 \sqrt{3)} }^{2} - {(2 \sqrt{2)} }^{2} } \\ = \frac{n}{27 - 8 } \\ = \frac{n}{19}$

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