Question

After rationalizing the denominator of 7/3√3-2√2​,we get the denominator as:
plz explain me the answer in detail

Answer 1

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\implies \frac{7}{3 \sqrt{3} } - 2 \sqrt{2} \\ \\ \implies \frac{7}{3 \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } - 2 \sqrt{2} \\ \\ \implies \frac{7 \sqrt{3} }{3 \times \sqrt{3 \times 3} } - 2 \sqrt{2} \\ \\ \implies \frac{7 \sqrt{3} }{3 \times 3} - 2 \sqrt{2} \\ \\ \implies \frac{7 \sqrt{3} }{9} - 2 \sqrt{2} \\ \\ \implies \frac{7 \sqrt{3} - 18 \sqrt{2} }{9} \\ \\ \implies \frac{7 \times 1.7 - 18 \times 1.4}{9} \\ \\ \implies \frac{ - 13.3}{9} \\ \\ \text{If \: question \: is-} \\ \implies \frac{7}{3 \sqrt{3} - 2 \sqrt{2} } \\ \\ \implies \frac{7}{3 \sqrt{3} - 2 \sqrt{2} } \times \frac{3 \sqrt{3} + 2\sqrt{2} }{ 3\sqrt{3} + 2 \sqrt{2} } \\ \\ \implies \frac{7(3 \sqrt{3} + 2 \sqrt{2} )}{ (3\sqrt{3})^{2} - ( {2 \sqrt{2)} }^{2} } \\ \\ \implies \frac{21 \sqrt{3} + 14 \sqrt{2} }{9 \times 3 - 4 \times 2} \\ \\ \implies \frac{20 \sqrt{3} + 14 \sqrt{2} }{27 - 8} \\ \\ \implies \frac{20 \sqrt{3} + 14\sqrt{2} }{19} \\ \\ \implies \frac{20 \times 1.7 + 14 \times 1.4}{19} \\ \\ \implies \frac{34 + 19.6}{19} \\ \\ \implies \frac{53.6}{19} \\ \\ \implies 2.82$